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pH is the negative logarithm of H^(+) ...

pH is the negative logarithm of `H^(+)`
` pH=log[H^(+)]`
`HCl lt H^(+)+Cl^(-)`
`H_(2)OhArrH^(+)+OH^(-)`
` K_(W)=[H^(+)][OH^(-)]`
`K_(W)` depend on the temperatue. With rise in temperature `K_(W)` increases.
At 298 K, pH of pure water = 7
The pH at first equivalance of `H_(3)PO_(4)` vs NaOH will be

A

7

B

`gt7`

C

`lt7`

D

Depend on the concentration of titrant

Text Solution

Verified by Experts

The correct Answer is:
C
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