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Partial pressure of N(2) gas at 298 K is...

Partial pressure of `N_(2)` gas at 298 K is 0.987 bargt If is bubbled through water at 298 K, how many millimoles of `N_(2)` gas would be dissolved in 1 litre of water ? (Given : `K_(H)` for `N_(2)` at 298 K =76.48 bar).

Text Solution

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`p=K_(H).x rArr x=(p)/(K_(H))`
`rArr x=(0.987)/(76.48xx10^(13))=1.29xx10^(-5)`
1 litre of water =55.5 mole of water
`rArrx=(n_(N_(2)))/(n_(N_(2))+55.5)~~(n_(N_(2)))/(55.5)=1.29xx10^(-5)`
`rArr n_(N_(2))=7.16xx10^(-4)"mol"`
=0.716 millimole
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