Home
Class 12
CHEMISTRY
Two liquids A and B are mixed to form an...

Two liquids A and B are mixed to form an ideal solution. The totol vapour pressure of the solution is 800 mm Hg. Now the mole fractions of liquid A and B are interchanged and the total vapour pressure becomes 600 mm of Hg. Calculate the vapour pressure of A and B in pure form. (Given :`p_(A)^(@)-p_(B)^(@)=100`)

Text Solution

Verified by Experts

`P_(A)=750" mm"` of Hg, `P_(B)=650" mm"` of Hg
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    AAKASH INSTITUTE|Exercise ASSIGMENT (SECTION-J) AAKASH CHALLENGERS QUESTIONS|10 Videos

  • SOLUTIONS

    AAKASH INSTITUTE|Exercise ASSIGMENT (SECTION-G) TRUE-FALSE TYPE QUESTIONS|5 Videos

  • REDOX REACTIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - D|10 Videos

  • SOME BASIC CONCEPT OF CHEMISTRY

    AAKASH INSTITUTE|Exercise ASSIGNMENT( SECTION - D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

The vapour pressure of pure liquid A and liquid B at 350 K are 440 mm and 720 mm of Hg. If total vapour [ressure of solution is 580 mm of Hg then the mole fraction of liquid A in vapour phase will be :-

If P_(A) is the vapour pressure of a pure liquid A and the mole fraction of A in the mixture of two liquids A and B is x, the parial vapour pressure of A is:

The vapour pressure of water at room temperature is 30 mm of Hg. If the mole fraction of the water is 0.9, the vapour pressure of the solution will be :

In binary ideal solution forms by liquid A and B, at constant temperature, mole -fraction of liquid A in vapour state is 0.4 and its partial vapour pressure is 400 mm,then what will be the partial vapour pressure of B ?