The conductivity of 0.25 M solution of KCI at 300 K is 0.0275 `cm^(-1)` calculate molar conductivity

Explanation

To calculate the molar conductivity of a 0.25 M solution of KCl at 300 K, we can follow these steps:

### Step 1: Understand the given data
- The conductivity (specific conductivity) of the solution, \( K \), is given as 0.0275 S/cm.
- The concentration of the solution, \( C \), is 0.25 M.

### Step 2: Recall the formula for molar conductivity
Molar conductivity (\( \Lambda_m \)) can be calculated using the formula:
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