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Given standard electrode potentials K^...

Given standard electrode potentials
`K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V`,
`Hg^(2+)|Hg=0.79V`
`Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V`
Arrange these metals in their increasing order of reducing power.

Text Solution

Verified by Experts

More negative the reduction potential more easily it is oxidsed nd hence greatere is the reducing power
thus increasing oreder of reduing power will be
`Ag lt Hg lt Cr kt Mg lt K`
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Given the standard electrode potentials, K^(+) | K = -2.93 V , Ag^(+) | Ag = 0.80 V , Hg_(2)^(2+) | Hg = 0.79 V , Mg_(2)^(2+) | Mg = -2.73 V , Cr_(2)^(3+) | Cr = -0.74 V . Arrange these metals in increasing order of their reducing power.