A 10 ampere current is passed through 500 ml NaCI solution for 965 seconds Calculate pH solution at the end of electrolysis

Explanation

`(W)/(E )=(1)/(96500)xxixxt`
`(W)/(E )=1/10`
So equivalents of NaOH formed =0.1
`N=(No of equivalents)/(V (in L)) =(0.1)/(500//1000)=0.2`
`[OH^(-)]=0.2`
`pOH=-log[OH^(-)]=-log0.2`
pOH=0.699
pOH=14-0.699=13.301