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Calculate degree of dissociation of 0.02...

Calculate degree of dissociation of 0.02 M acetic acid at 298 K given that `mho_(m)(CH_(3)COOH)=17.37 cm^(2) mol^(-1),lambda_(m)^(@)(H+)=345.8 S cm^(2) mol^(-1), lambda_(m)^(@)(CH_(3)COO^(-))=40.2 Scm^(2) mol^(-1)`

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Calculate degree of dissocation of 0.02 M acetic acid at 298K. Given that Lamda_(m) (CH_(3)COOH)= 17.37 S cm^(2) mol^(-1), lamda_(m)^(@) (H^(+)) = 345.8 S cm^(2) mol^(-1), lamda_(m)^(@) (CH_(3)COO^(-)) = 40.2S cm^(2) mol^(-1)

Calculate the degree of dissociation of 0.02 M acetic acid at 298K, given that lambda_(CH_(3)COOH)=11.7ohm^(-1)cm^(2)"mol"^(-1) lambda_((CH_(3)COO^(-)))=40.9ohm^(-1)cm^(2)"mol"^(-1) lambda(H^(+))^(@)=349.1ohm^(-1)cm^(2)"mol"^(-1)

Calculate the degree of dissociation (alpha) of acetic acid if its molar conductivity (^^_(m)) is 39.05 S cm^(2) mol^(-1) Given lamda^(@) (H^(+)) = 349.6 cm^(2) mol^(-1) and lamda^(2) (CH_(3)COO^(-)) = 40.9 S cm^(2) mol^(-1)

The equivalent conductances of sodium chloride, hydrochloric acid and sodium acetate at infinite dilution are 126.45, 426.16 and 91.0ohm^(-1) cm^(-1)"equiv"^(-1) , respectively, at 25^(@)C . Calculate the equivalent conducatance of acetic acid at infinite dilution. Lambda_(m)^(0)(HCl)="426.16 S cm"^(2)mol^(-1) Lambda_(m)^(0)(NaCl)="126.45 S cm"^(2)mol^(-1) Lambda_(m)^(0)(CH_(3)COONa)="91 S cm"^(2)mol^(-1)

(a) Calculate the degree of dissociation of 0.0024 M acetic acid if conductivity of this solution is 8.0 xx 10^(-5)" S "cm^(-1) . Given . lambda_(H^(+))^(@) = 349.6" S " cm^(2)" mol"^(-1), lamda_(CH_(3)COO^(-))^(@)= 40.9" S " cm^(2) " mol "^(-1) (b) Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The limiting molar conductivity of ‘B’ increases to a smaller extent while that of ‘A’ increases to a much larger extent comparatively. Which of the two is a strong electrolyte? Justify your answer.

Calculate Lambda_(m)^(oo) for acetic acid, given, Lambda_(m)^(oo)(HCl)=426 Omega^(-1)cm^(2)mol^(-1),Lambda_(m)^(oo)(NaCl)=126Omega^(-1)cm^(2)mol^(-1) , Lambda_(m)^(oo)(CHCOONa)=91Omega^(-1)cm^(2)mol^(-1)

Calcualte acid dissociatioin constant for 0.1 M HCOOH if its solution shows a resistance of 50 Omega filled in a cell having separation beween parallel electrodes 4 cm and cross section area of electrode 10 cm^(2) . [Given: Lambda_(m)^(infty)[Ca(HCCO)_(2)] = 230 Scm^(2)mol^(-) lambda_(m)^(infty)[CaCl_(2)] = 280 Scm^(2) mol^(-1) lambda_(m)^(infty) [HCl] = 425 Scm^(2) mol^(-1) ] In scientific notation, x xx 10^(-y) , find the value of y.

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