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Calculate the equilibrium constant for the reaction at 298K.
`Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s)`
Given, `E_(Zn^(2+)//Zn)^(@) =- 0.76V` and `E_(Cu^(2+)//Cu)^(@) = +0.34 V`

A

after electrolysis `Zn^(+2)` concentration is 1.36 M

B

after electrolysis `Cu^(+2)` concentration is 0.64 M

C

after electrolysis `Zn^(+2)` concentration is 0.82 M

D

after electrolysis `Cu^(+2)` concentration is 1.18 M

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