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The resistacnce of a conductivity cell f...

The resistacnce of a conductivity cell filled with 0.01 N KCI at `25^(@)` was found to be 500 `Omega` The specific conductance of 0.01 N KCI at `25^(@)` is `1.41xx10^(-3) Omega^(-) cm^(-1)` The resistance of same cell filled with `0.3 N ZnSO_(4)` at `25^(@)C` was found to be 69 `Omega` Calculate the cell constant equivalent and molar conductivityes of `ZnSO_(4)` solution

Text Solution

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Cell constant =0.705 `cm^(-1)`
Equivalent conductivity `=34.1 Omega^(-1)cm^(-1)eq^(-1)`
Molar conductivity `=68.2 Omega^(-1) cm^(-1) mol^(-1)`
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