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Neglecting the liquid-liquid junction po...

Neglecting the liquid-liquid junction potential, calculate the emf of the following cell at `25^(@)C`
`H_(2) (1 atm)|0.5 M HCOOH|| 1M CH_(3)COOH | (1 atm) H_(2)`
`K_(a) " for " HCOOH and CH_(3) COOH` are `1.77 xx 10^(-4) and 1.8 xx 10^(-5)` respectively.

Text Solution

Verified by Experts

`E_(cell)=-0.0204 V`
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