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A,B and C are three complexes of chromiu...

`A,B` and `C` are three complexes of chromium(III) with the empirical formula `H_(12)O_(6)C_(13)Cr` All the three complexes not react with concentrated `H_(2)SO_(4)` whereas complexes `B` and `C` lose `6.75%` and `13.5%` of their original mass respectively, on treatment on treatment with conectrated `H_(2)SO_(4)` Identify `A,B` and `C` .

Text Solution

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`A=[Cr(H_(2)O)_(6)]Cl_(3) overset(H_(2)SO_(4))to` No reaction
( `:'` All `H_(2)O` molecules are present in coordination sphere )
`B=[CrCl(H_(2)O)_(5)]Cl_(2).H_(2)O overset(H_(2)SO_(4))to` one mole of `H_(2)O` is lost
Molecular weight of complex =266.5
`% "loss"=(18)/(266.5)xx100=6.75%`
`C=[CrCl_(2)(H_(2)O)_(4)]Cl_(2).2H_(2)O overset(H_(2)SO_(4))to` 2 moles of `H_(2)O` removed
`:.` % loss in weight `=(2xx 18)/(266.5)xx100=13.50% `
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A, B and C are three complexes of chromium (III) with the empirical formula H_(12)O_(6)Cl_(3)Cr . All the three complexes have water and chloride ion as ligands. Complex A does not react with concentrated H_(2)SO_(4) , whereas complexes B and C lose 6.75% and 13.5% of their original weight, respectively, on treatment with concentrated H_(2)SO_(4) . Which type of isomerism is possible in complex C?

A, B and C are three complexes of chromium (III) with the empirical formula H_(12)O_(6)Cl_(3)Cr . All the three complexes have water and chloride ion as ligands. Complex A does not react with concentrated H_(2)SO_(4) , whereas complexes B and C lose 6.75% and 13.5% of their original weight, respectively, on treatment with concentrated H_(2)SO_(4) . According to the Werner theory, the structure of complex A is represented by :