Home
Class 12
CHEMISTRY
Optically active 2-iodo butane on treatm...

Optically active 2-iodo butane on treatment with `NaI` in acetone gives a product which does not show optical activity. Explain briefly.

Text Solution

Verified by Experts

In this reaction C - I bond is broken and reformed to give a racemic mixture of 2- iodobutane and thus remains optically inactive .The presence of `I^(-)` provides opportunity for the remaking of the C- I bond
Promotional Banner

Topper's Solved these Questions

  • HALOALKANES AND HALOARENES

    AAKASH INSTITUTE|Exercise Assignment (Section - A ) ( Competition Level Question )|50 Videos

  • HALOALKANES AND HALOARENES

    AAKASH INSTITUTE|Exercise Assignment (Section - B ) ( Objective Type Question(One option is correct ))|37 Videos

  • HALOALKANES AND HALOARENES

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION -D|15 Videos

  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    AAKASH INSTITUTE|Exercise Try Yourself|33 Videos

  • HYDROCARBONS

    AAKASH INSTITUTE|Exercise Assignment(Section - D) (Assertion -Reason Type Question)|24 Videos

Similar Questions

Explore conceptually related problems

Optically active 2-iodo burtane on treatment with NaI in acetone gives a product which does not show optical activity. Explain briefly.

Iodoform is obtained by the reaction of acetone with hypoiodite but not with iodide I on. Explain. (b) Optically active 2-iodobutane on treatment with Nal in acetone gives a product which does not show optical activity. Why?

Optically active (S)-2-iodooctane with Nal in acetone gives a product which does not show optical activity. Explain.

Which of the following does not show optical activity ?