The number of isomer (including stereoisomers) of `C_(5)H_(12)O` which can give positive haloform test is

Explanation

To determine the number of isomers (including stereoisomers) of C₅H₁₂O that can give a positive haloform test, we can follow these steps:

### Step 1: Identify the structure of C₅H₁₂O
C₅H₁₂O can represent several types of compounds, including alcohols, ethers, and ketones. However, for the haloform test, we need to focus on compounds that can form a methyl ketone upon oxidation.

### Step 2: Understand the haloform test
The haloform test is positive for compounds that can produce a methyl ketone (RCOCH₃) upon oxidation. Therefore, we need to identify isomers of C₅H₁₂O that can be oxidized to form a methyl ketone.

### Step 3: Identify possible isomers
The possible structural isomers of C₅H₁₂O include:
1. **Pentanol isomers** (1-pentanol, 2-pentanol, 3-pentanol, etc.)
2. **Cyclopentanol**
3. **Ethers** (e.g., methyl butyl ether)

### Step 4: Determine which isomers can give a positive haloform test
- **1-Pentanol**: Cannot give a positive haloform test.
- **2-Pentanol**: Can be oxidized to methyl ketone (acetone).
- **3-Pentanol**: Cannot give a positive haloform test.
- **Cyclopentanol**: Cannot give a positive haloform test.
- **Ethers**: Generally do not give a positive haloform test.

### Step 5: Count stereoisomers
2-Pentanol has one chiral center, which means it can exist as two stereoisomers (R and S forms).

### Conclusion
The only isomer of C₅H₁₂O that can give a positive haloform test is 2-pentanol, which has two stereoisomers. Therefore, the total number of isomers (including stereoisomers) that can give a positive haloform test is **2**.

### Final Answer
The number of isomers (including stereoisomers) of C₅H₁₂O that can give a positive haloform test is **2**.

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