A particle starts from the origin, goes along x-axis to the point (10 m, 0) and then returns along. The same line to the point (-10 m, 0). The distance and displacement of the particle during the trip are

Options

A. 20 m, 0
B. 30 m, 10 m
C. 30 m, - 10 m
D. 20 m, 10 m

Answer

To solve the problem, we will calculate both the distance and displacement of the particle during its trip.

### Step-by-Step Solution:

1. **Understanding the Motion**:
- The particle starts at the origin (0 m).
- It moves to the point (10 m, 0) along the x-axis.
- Then, it returns along the same line to the point (-10 m, 0).

2. **Calculating the Distance**:
- The distance is the total length of the path traveled by the particle.
- First, the particle travels from 0 m to 10 m, which is a distance of 10 m.
- Then, it returns from 10 m to -10 m. The distance for this return journey is:
- From 10 m to 0 m: 10 m
- From 0 m to -10 m: 10 m
- Therefore, the total distance traveled is:
\[ \text{Total Distance} = 10 \, \text{m} + 10 \, \text{m} + 10 \, \text{m} = 30 \, \text{m} \]

3. **Calculating the Displacement**:
- Displacement is defined as the change in position from the initial point to the final point.
- The initial position is 0 m and the final position is -10 m.
- Therefore, the displacement is:
\[ \text{Displacement} = \text{Final Position} - \text{Initial Position} = -10 \, \text{m} - 0 \, \text{m} = -10 \, \text{m} \]

### Final Answers:
- **Distance**: 30 m
- **Displacement**: -10 m