Home
Class 12
PHYSICS
Four particles of masses 1kg, 2kg, 3kg a...

Four particles of masses 1kg, 2kg, 3kg and 4kg are placed at the four vertices A, B, C and D of a square of side 1m. Find the position of centre of mass of the particles. Assume that D is situated at the origin.

Text Solution

Verified by Experts

A suitable choice of axis will be through the sides of the square as shown. Consider `1kg` at origin. Position coordinates of respective masses are shown in figure.

`X=(1xx0+2xxa+3xxa+4xx0)/(10)=(a)/(2)`
`Y=(1xx0+2xx0+3xxa+4xxa)/(10)=(7)/(10)a`
`Z=0`
Coordinates of centrre of mass of the system are `((a)/(2),(7)/(10)a,0)`
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE|Exercise Illustration|4 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE|Exercise Assignment (Section - A) Objective Type Questions (One option is correct)|62 Videos
  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    AAKASH INSTITUTE|Exercise Assignment (Section-D (Assertion and reason))|5 Videos
  • TEST 1

    AAKASH INSTITUTE|Exercise EXERCISE|9 Videos

Similar Questions

Explore conceptually related problems

Four particles of masses 1kg , 2kg , 3kg and 4kg are placed at the four vertices A,B,C and D of a square of side 1m . Find square of distance of their centre of mass from A.

Particle of masses 2 kg, 2 kg, 1 kg and 1 kg are placed at the corners A, B, C, D of a square of side L as shown in Fig. Find the centre of mass of the system.

Four particles of masses 1 kg, 2 kg, 3 kg, 4 kg are placed at the corners of a square of side 2 m. Find the coordinates of centre of mass.

Four particles of masses m, m, 2m and 2m are placed at the four corners of square of side a. Find the centre of mass of the system.

Four bodies of masses 2, 3, 5 and 8 kg are placed at the four corners of a square of side 2 m. The position of CM will be -

Four particles of masses 4 kg, 2 kg, 3kg and 5 kg are respectively located at the four corners A, B, C, D of a square of side 1 m . Calculate the moment of inertia of the system about (i) the axis passing through point of intersection of the diagonals and perpendicualr to the plane of the square. (ii) side AB (ii) diagonal BD .

Three particles of masses 1kg , 2kg and 3kg are placed at the corners A, B and C respectively of an equilateral triangle ABC of edge 1m . Find the distance of their centre of mass from A.

Four particles of mass 2 kg, 3kg, 4 kg and 8 kg are situated at the comers of a square of side length 2 m. The centre of mass may be given as

Four particles of masses 1kg ,2kg, 3kg and 4kg are placed at the corners of a square of side 2m in the x-y plane If the origin of the co-ordinate system is taken at the mass of 1kg, the (x,y) co-ordinates of the enter of mass expressed in metre are :

AAKASH INSTITUTE-SYSTEM OF PARTICLES AND ROTATIONAL MOTION-Try Yourself
  1. Four particles of masses 1kg, 2kg, 3kg and 4kg are placed at the four ...

    Text Solution

    |

  2. Two bodies of masses 1kg and 3kg are lying in xy plane at (0,0) and (2...

    Text Solution

    |

  3. Three point masses of 1kg, 2kg and 3kg lie at (0,0), (1,2), (3,-1) res...

    Text Solution

    |

  4. Three particles of masses m,m and 4kg are kept at a verticals of trian...

    Text Solution

    |

  5. Three particles having their masses in the ratio 1 : 3 : 5 are kept at...

    Text Solution

    |

  6. Centre of mass of the system lies inside disc or square plate and why ...

    Text Solution

    |

  7. Two particles of equal mass are moving along the same line with the sa...

    Text Solution

    |

  8. Two particles of equal mass are moving along the same straight line wi...

    Text Solution

    |

  9. A shell following a parabolic path explodes somewhere in its flight. T...

    Text Solution

    |

  10. All the particles are situated at a distance R from the origin. The di...

    Text Solution

    |

  11. Will the velocity and acceleration of centre of mass change if particl...

    Text Solution

    |

  12. vecA=(3hati+2hatj-6hatk) and vecB=(hati-2hatj+hatk), find the scalar p...

    Text Solution

    |

  13. vecA=(hati-2hatj+6hatk) and vecB=(hati-2hatj+hatk), find the cross pro...

    Text Solution

    |

  14. Find a unit vector in the direction of vector vecA=(hati-2hatj+hatk)

    Text Solution

    |

  15. Find a vector perpendicular to vector vecA=(hati+2hatj-3hatk) as well ...

    Text Solution

    |

  16. The angular displacement of a particle is 24 rad in 10 seconds. Calcul...

    Text Solution

    |

  17. The angular velocity of a rigid body is 24 rad s^(-1), Calculate the t...

    Text Solution

    |

  18. The angular velocity of circular disc of radius 2cm is 20 rad s^(-1). ...

    Text Solution

    |

  19. What is the angular velocity of a particle lying on the axis of rotati...

    Text Solution

    |

  20. What is the angular acceleration of a particle moving with constant an...

    Text Solution

    |

  21. A wheel is rotating with an angular velocity of 3 rad s^(-1). If the a...

    Text Solution

    |