Home
Class 12
PHYSICS
A disc of mass M has a light, thin strin...

A disc of mass `M` has a light, thin string wrapped several times around its circumference. The free end of string is attaced to the ceiling and the disc is released from rest. Find the acceleration of the disc and the tension in the string.

Text Solution

Verified by Experts

We draw the F.B.D of disc assuming tension to be `T`

Applying Newton's Second Law
`sumF=Ma_(CM)=ltMg-T=Ma`
`sumtau_(CM)=I_(CM)*alpha`
`impliesT.R=(MR^(2))/(2)*alpha=(MR(R alpha))/(2)=(Ma)/(2)` [`:' a=alphaR`]
`implies a=(2g)/(3)` and `T=(Mg)/(3)`
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE|Exercise Illustration|4 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE|Exercise Assignment (Section - A) Objective Type Questions (One option is correct)|62 Videos
  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    AAKASH INSTITUTE|Exercise Assignment (Section-D (Assertion and reason))|5 Videos
  • TEST 1

    AAKASH INSTITUTE|Exercise EXERCISE|9 Videos

Similar Questions

Explore conceptually related problems

A uniform round object of mass M , radius R and moment of inertia about its centre of mass I_(cm) has a light, thin string wrapped several times around its circumference. The free end of string is attaced to the celling and the object is released from rest. Find the acceleration of centre of the object and tension n the string. [ Take (I_(cm))/(MR^(2))=k ]

A solid cylinder has a thin string wrapped several times around its circumference. The string is fixed at one end and the cylinder is released. Find the downward acceleration of cylinder and tension in the string.

A string is wrapped several times round a solid cylinder. Then free end of the string is held stationary. If the cylinder is released to move down, then the acceleration of that cylinder is

The block of mass m is at rest. Find the tension in the string A .

The system shown in figure is released is released from rest . Find acceleration of different string blocks and tenson in different strings.

A string is wrapped over the edge a uniform disc and the free end is fixed with the ceiling. The disc moves down, unwinding the string. Find the downward acceleration of the disc.

The pulley is light and smooth : the strings are inextensible and light. The system is released from rest, find the acceleration of each block, tensions in the strings and reaction in pulley.

Two bodies of masses 2kg and 3kg are connected by a very light string passed over a clamped light smooth pulley. If the system is released from rest, find the acceleration of the two masses and the tension in the string (g=10m s^(-2) )

A uniform disc of radius R and mass M is free to rotate only about its axis. A string is wrapped over its rim and a body of mass m is tied to the free end of the string as shown in the figure. The body is released from rest. Then the acceleration of the body is

In the system shown in figure, the block A is released from rest. Find Tension in the string.

AAKASH INSTITUTE-SYSTEM OF PARTICLES AND ROTATIONAL MOTION-Try Yourself
  1. A disc of mass M has a light, thin string wrapped several times around...

    Text Solution

    |

  2. Two bodies of masses 1kg and 3kg are lying in xy plane at (0,0) and (2...

    Text Solution

    |

  3. Three point masses of 1kg, 2kg and 3kg lie at (0,0), (1,2), (3,-1) res...

    Text Solution

    |

  4. Three particles of masses m,m and 4kg are kept at a verticals of trian...

    Text Solution

    |

  5. Three particles having their masses in the ratio 1 : 3 : 5 are kept at...

    Text Solution

    |

  6. Centre of mass of the system lies inside disc or square plate and why ...

    Text Solution

    |

  7. Two particles of equal mass are moving along the same line with the sa...

    Text Solution

    |

  8. Two particles of equal mass are moving along the same straight line wi...

    Text Solution

    |

  9. A shell following a parabolic path explodes somewhere in its flight. T...

    Text Solution

    |

  10. All the particles are situated at a distance R from the origin. The di...

    Text Solution

    |

  11. Will the velocity and acceleration of centre of mass change if particl...

    Text Solution

    |

  12. vecA=(3hati+2hatj-6hatk) and vecB=(hati-2hatj+hatk), find the scalar p...

    Text Solution

    |

  13. vecA=(hati-2hatj+6hatk) and vecB=(hati-2hatj+hatk), find the cross pro...

    Text Solution

    |

  14. Find a unit vector in the direction of vector vecA=(hati-2hatj+hatk)

    Text Solution

    |

  15. Find a vector perpendicular to vector vecA=(hati+2hatj-3hatk) as well ...

    Text Solution

    |

  16. The angular displacement of a particle is 24 rad in 10 seconds. Calcul...

    Text Solution

    |

  17. The angular velocity of a rigid body is 24 rad s^(-1), Calculate the t...

    Text Solution

    |

  18. The angular velocity of circular disc of radius 2cm is 20 rad s^(-1). ...

    Text Solution

    |

  19. What is the angular velocity of a particle lying on the axis of rotati...

    Text Solution

    |

  20. What is the angular acceleration of a particle moving with constant an...

    Text Solution

    |

  21. A wheel is rotating with an angular velocity of 3 rad s^(-1). If the a...

    Text Solution

    |