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Moment of inertia of a half ring of mass...

Moment of inertia of a half ring of mass `m` and radius `R` about an axis passing through point `A` perpendicular to the plane of the paper is `I_(A)`. If `I_(C )` is the moment of inertia of the ring about an axis perpendicular to the plane of paper and passing through point `C`, then

A

`I_(A)=I_(C )+mR^(2)`

B

`I_(A) gt I_(C )+mR^(2)`

C

`I_(A) lt I_(C )+mR^(2)`

D

None of these

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Knowledge Check

  • Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is

    A
    `1//2MR^(2)`
    B
    `MR^(2)`
    C
    `1//4MR^(2)`
    D
    `3//4 MR^(2)`

  • In the above problem the moment of inertia of four bodies about an axis perpendicular to the plane of frame and passing through a corner is

    A
    `ML^(2)`
    B
    `2ML^(2)`
    C
    `2sqrt(2)ML^(2)`
    D
    `4ML^(2)`

  • In the above problem the moment of inertia of four bodies about an axis perpendicular to the plane of frame and passing through a corner is

    A
    `ML^(2)`
    B
    `2ML^(2)`
    C
    `2sqrt(2)ML^(2)`
    D
    `4ML^(2)`

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