Home
Class 12
PHYSICS
A uniform disc (of mass M and radius a) ...

A uniform disc (of mass `M` and radius `a`) has a hole (of radius `b`) drilled through it. The centre of the hole is at a distance `c` from the centre of the original disc. What is the moment of inertia of the disc about an axis through the centre of the disc and perpendicular to its plane ?

Text Solution

Verified by Experts

`(1)/(2)(M)/(a^(2)-b^(2))(a^(4)-b^(4)-2b^(2)c^(2))`
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE|Exercise Assignment (Section - J) Aakash Challengers Questions|13 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE|Exercise Try Yourself|63 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTION

    AAKASH INSTITUTE|Exercise Assignment (Section - H) Multiple True-False Type Questions|4 Videos
  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    AAKASH INSTITUTE|Exercise Assignment (Section-D (Assertion and reason))|5 Videos
  • TEST 1

    AAKASH INSTITUTE|Exercise EXERCISE|9 Videos

Similar Questions

Explore conceptually related problems

The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

If a circular concentric hole is made on a disc then about an axis passing through the centre of the disc and perpendicular to its plane

Calculate the moment of inertia of a disc of radius R and mass M, about an axis passing through its centre and perpendicular to the plane.

Radius of gyration of a uniform circular disc about an axis passing through its centre of gravity and perpendicular to its plane is

A disc of radius R has a concentric hole of radius R /2 and its mass is M. Its moment of inertia about an axis through its centre and perpendicular to its plane, is

Find the position of centre of mass of a uniform disc of radius R from which a hole of radius is cut out. The centre of the hole is at a distance R/2 from the centre of the disc.

Calculate the moment of inertia of uniform circular disc of mass 500 g, radius 10 cm about : the axis through the centre of the disc and perpendicular to its plane

The moment of inertia of a uniform semicircular disc of mass disc through the centre is

A disc of mass m and radius R, is placed on a smooth text service fixed surface . Point A is the geometrical centre of the disc while point B is the centre of mass of the disc . The moment of inertia of the dics about an axis through its centre of mass and perpendicular to the plane of the figure is I .A constant force F is applied to the top of the disc . The acceleration of the centre A of the disc at the instant B is below A (on the same vertical line ) will be :