`vecA=(hati-2hatj+6hatk)` and `vecB=(hati-2hatj+hatk)`, find the cross product between `vecA` and `vecB`.

Explanation

`vecAxxvecB=|{:(hati,hatj,hatk),(1,-2,6),(1,-2,1):}|=hati(-2+12)+hatj(6-1)+hatk(-2+2)`
`=10hati+5hatj`
Hint. `vecAxxvecB=|{:(hati,hatj,hatk),(A_(x),A_(y),A_(z)),(B_(x),B_(y),B_(z)):}|`