A force `(hati-2hatj+3hatk)` acts on a particle of position vector `(3hati+2hatj+hatk)`. Calculate the `hatj^(th)` component of the torque acting on the particle.

Explanation

`vectau=vecrxxvecF`
`=|{:(hati,hatj,hatk),(3,2,1),(1,-2,3):}|=hati(6+2)+hatj(1-9)hatk(-6-2)`
`=8hati-8hatj-8hatk`
`=8(hati-hatj-hatk)`
The `hatj^(th)` component of the torque is `-8`