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A torque of 5Nm is applied on a particle...

A torque of `5Nm` is applied on a particle for `2` seconds, calculate the change in its angular momentum.

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`(dL)/(dt)=vectau`
`impliesdL=2xx5=10kgm^(2)//s`
Hint. `vectau=(dvecL)/(dt)`
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