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The angular momentum of a particle chang...

The angular momentum of a particle changes from `4kg m^(2)s^(-1)` to `8kg m^(2)s^(-1)` is `2` seconds. Calcualte the torque acting on the particle

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`(dL)/(dt)=(8-4)/(2)=(4)/(2)=2Nm`
Hint. `vectau=(dvecL)/(dt)`
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