Calculate the moment of inertia of the given rod about an axis `CD`

Explanation

Moment of inertia of the rod about `AB=(MI^(2))/(12)`
using parallel axis theorem
`I_(CD)=(MI^(2))/(12)+M((I)/(4))^(2)=(MI^(2))/(12)+(MI^(2))/(16)=(7)/(48)MI^(2)`

Hint : Use parallel axis theorem.