The angular velocity of a motor wheel changes from `180` rpm to `300` rpm in `4` seconds. Calculate the no. of revolutions does the engine make during this time.

Explanation

`omega=omega_(0)+alpha t`
`implies((300-180))/(60)=alphaxx4`
`impliesalpha=(2)/(4)=0.5 rev//s^(-2)`
using `theta=omega_(0)t+(1)/(2)alphat^(2)`
`=(180)/(60)xx4+(1)/(2)xx0.5xx16`
`=16` revolution
Hint : Use kinematic equations of rotational motion.