Calculate the velocity with which a solid cylinder rolls down an inclined plane of height `10m` with slipping (take `g=10m//s^(2)`)

Explanation

`M.I.` of solid cylinder `=(1)/(2)MR^(2)`
`K=(1)/(sqrt(2))R`
`v=sqrt((2xx10xx10)/((1+(1)/(2))))=sqrt((2xx10xx10xx2)/(3))=(20)/(sqrt(3))m//s`
Hint : `v=sqrt((2gh)/((1+(k^(2))/(R^(2)))))`