Three balls each of mass 0.5 kg are kept at the vertices of an isosceles right triangle with its hypotenuse of `2sqrt(2)` m. What will be the net gravitational force on the ball kept at the vertex of right angle ?

Explanation

Let BA = BC = r
`therefore r^(2)+r^(2)=(2sqrt(2))^(2)`
`therefore 2r^(2)=4xx2`
`therefore r=2m`

`vec(F)_("net")` on `B=vec(F)_(BA)+vec(F)_(BC)`
`|vec(F)_(BA)|=(G(0.5)(0.5))/(2^(2))=(6.67xx10^(-11)xx0.25)/(4)=4.17xx10^(-12)N`
and `|vec(F)_(BC)|=(G(0.5)(0.5))/(2^(2))=(6.67xx10^(-11)xx0.25)/(4)=4.17xx10^(-12)N`
`|vec(F)_("net")|^(2)=|vec(F)_(BA)|^(2)+|vec(F)_(BC)^(2)=2|vec(F)_(BA)|^(2)`
`therefore |vec(F)_("net")|=sqrt(2)(4.17xx10^(-12))N=5.84xx10^(-12)N` .