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What will be the escape speed from a pla...

What will be the escape speed from a planet having radius thrice that of earth and the same mean density as that of the earth ? (Take `v_(e)=11.2` km/s)

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The correct Answer is:
33.6 km/s

Hint `v=sqrt((2G(4)/(3)pi R^(3)rho)/(R ))`
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The escape velocity from the earth is 11 km//s . The escape velocity from a planet having twice the radius and same density as that of the earth is (in km//s )

Statement-1 : Th escape valocity from the earth is upsilon_(e) . Th esacpe velocity from a planet whose radius to twice that of the earth and mean density is same as that of the earth is 2 upsilon_(e) . Statement-2 : upsilon_(e) = sqrt(g R)

The escape Velocity from the earth is 11.2 Km//s . The escape Velocity from a planet having twice the radius and the same mean density as the earth, is :

The escape velocity form the earth is 11 kms^(-1) the esacpe velocity from a planet having twice the radius and the same mean denisty as the earth would be

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