Home
Class 12
PHYSICS
Time period of a satellite in a circular...

Time period of a satellite in a circular obbit around a planet is independent of

A

Radius of the orbit

B

Mass of the planet

C

Mass of the statellite

D

Radius of the planet

Text Solution

Verified by Experts

The correct Answer is:
C, D
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION -D (Linked Comprehension Type Questions)|13 Videos

  • GRAVITATION

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION -E (Assertion - Reason Type Questions)|14 Videos

  • GRAVITATION

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION -B (Objective Type Questions (one option is correct))|20 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - D|13 Videos

  • KINETIC THEORY

    AAKASH INSTITUTE|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|10 Videos

Similar Questions

Explore conceptually related problems

The time period of a satellite in a circular orbit around the earth is T . The kinetic energy of the satellite is proportional to T^(-n) . Then, n is equal to :

The time period of a satellite in a circular orbit of radius R is T. The period of another satellite in a circular orbit of radius 9R is :

The period of a satellite in a circular orbit of radius R is T , the period of another satellite in a circular orbit of radius 4R is

The period of a satellite in circcular orbit of radius 12000 km around a planet is 3h. What is the period o a satellite in circular orbit of radius 48000 km around the same planet ?

The time period of a satellite in a circular orbit of radius R is T. The radius of the orbit in which time period is 8 T is

The time period of an earth satelite in circular orbit is independent of

Statement I: If time period of a satellite revolving in circular orbit in equatorial plane is 24 h , then it must be a, geostationary satellite. Statement II: Time period of a geostationary satellite is 24 h .