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The time period of earth's rotation shou...

The time period of earth's rotation should be `x pi sqrt((R_(e))/(g))` if the weight of a body at equator become 3/4 times of its actual weight. Find the vlaue of x.

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Explore conceptually related problems

What should be the angular velocity of rotation of Earth about its own axis so that the weight of body at the equator reduces to 3/5 of its present value? (Take R as the radius of the Earth)

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Knowledge Check

  • If the speed of rotation of earth about its axis increases, then the weight of the body at the equator will

    A
    increases
    B
    decreases
    C
    remains unchanged
    D
    some times decreases sometimes increases

  • The height a which the weight of a body becomes 1//16th its weight on the surface of earth (radius R ) is

    A
    `4R`
    B
    `5R`
    C
    `15R`
    D
    `3R`

  • What should be the angular velocity of earth about its own axis so that the weight of the body at the equator would become 3/4 th of its present value ?

    A
    `1/400 rads^(-1)`
    B
    `1/800 rad s^(-1)`
    C
    `1/1600 rad s^(-1)`
    D
    `1/3200 rad s^(-1)`

    • Similar Questions

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    Find the value of angular velocity of axial rotation of the earth, such that weight of a person at equator becomes 3/4 of its weight at pole, Radius of the earth at equator is 6400 km.

    The height at which the weight of the body become 1/9 th its weight on the surface of earth (radius of earth R)

    The angular speed of rotation of earth about its axis at which the weight of man standing on the equator becomes half of his weight at the poles is given by

    What should be the velocity of rotation of earth due to rotation about its own axis so that the weight of a person becomes 3/5 of the present weight at the equator. Equatorial radius of the earth is 6400 km.

    What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km

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