Home
Class 12
PHYSICS
If x(1) is the magnitude of gravitationa...

If `x_(1)` is the magnitude of gravitational potential excatly midway between earth and surface and `x_(2)` is the square of angular velocity of rotation of earth around its own axis such that alll bodies equator are in square of angular velocity of rotation of earth around its own axis such that al bodies equator are in floating position. Now if `(x_(1))/(x_(2))=[1+(3)/(x)]R^(2)`. Find the value of x.

Text Solution

Verified by Experts

The correct Answer is:
8
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION -H (Multiple True - False Type Questions)|5 Videos
  • GRAVITATION

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION -I (Subjective Type Question)|9 Videos
  • GRAVITATION

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION -F (Matrix - Match Type Questions)|9 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - D|13 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|10 Videos

Similar Questions

Explore conceptually related problems

What is angular velocity of earth spinning around its own axis ?

Which is greater , the angular velicty of the hour hand of a watch or angular velocity of earth around its own axis ?

What should be the angular velocity of rotation of Earth about its own axis so that the weight of body at the equator reduces to 3/5 of its present value? (Take R as the radius of the Earth)

Which is greater : the angular velocity of hour hand of a watch or angular velocity of earth around its own axis ? Give their ratio.

If omega_(E ) is the angular velocity of the earth rotating about its own axis and omega _(H) is the angular velocity of the hour of a clock , then

Find the value of angular velocity of axial rotation of the earth, such that weight of a person at equator becomes 3/4 of its weight at pole, Radius of the earth at equator is 6400 km.

If R is radius of the earth omega is present angular velocity about its axis, the value of g at the equator varies like this on stopping the rotation of the earth

What should be the angular velocity of earth about its own axis so that the weight of the body at the equator would become 3/4 th of its present value ?

If omega is the angular velocity of rotation of the earth about its axis and R is radius of the earth, to decrease the weight of a body near the equator by 40% , then the new angular speed should be