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A body is suspended on a spring balance ...

A body is suspended on a spring balance in a ship sailing along the equator with a speed `v`. Show that the scale reading will be very close to `W_(0)(1 pm (2 omega v)/(g))`, where `omega` is the angular speed of the earth and `W_(0)` is the reading of spring balance when the ship is at rest. Explain the plus or minus sign
[Hint : `W_(0)=mg-momega^(2)R,W=mg-m((momega+v)^(2))/(R)` when the ship is moving from west to east]

Answer

Step by step text solution for A body is suspended on a spring balance in a ship sailing along the equator with a speed v. Show that the scale reading will be very close to W_(0)(1 pm (2 omega v)/(g)), where omega is the angular speed of the earth and W_(0) is the reading of spring balance when the ship is at rest. Explain the plus or minus sign [Hint : W_(0)=mg-momega^(2)R,W=mg-m((momega+v)^(2))/(R) when the ship is moving from west to east] by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

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A body suspended on a spring balance in a ship weighs W_(0) when the ship is at rest. When the ship begins to move along the equator with a speed v , show that the scale reading is very close to W_(0) (1+-2omegaV//g ), where omega is the angular speed of the earth.

What will be the reading of spring balance in the figure shown in following situations ( g = 10 m//s^(2) ) a= 0, v = 0

Knowledge Check

  • A body is responded on a spring balance in a ship sailing along the equator with speed V. If w is the angular speed of the earth and w_(0) is the scale reading when ship is at rest, the scale reading when the ship is sailing is

    A
    `w_(0)`
    B
    zero
    C
    `W_(0)(1 pm (2wv)/(g))`
    D
    `W_(0)(1- (g)/(2w))`

  • A body is suspended on a spring balance in a ship sailing along the equator with a speed v'. If omega is the angular speed of the earth and omega_(0) is the scale reading when the ship is at rest, the scale reading when the ship is sailing is

    A
    `omega_(0)`
    B
    zero
    C
    `omega_(0) (1+-(2omega v')/(g))`
    D
    `omega_(0)(1-(g)/(2omega))`

  • A body is weighed with a spring balance in a train at rest, shown a weight W . When the train begins to move with a velocity upsilon around the equator from west to east and if the angular velocity of the train is omega then the weight shown by spring balance is

    A
    `W`
    B
    `W(1- (2 upsilon omega)/(g))`
    C
    `W(1- (2 upsilon omega)/(g))`
    D
    `W (1 - upsilon^(2)//R)`

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