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At what velocity does the water emerge f...

At what velocity does the water emerge from an orifice in an open tank if the gauge pressure at the orifice is `2 xx 10^(5) N m^(-2)` before the flow starts?

Text Solution

Verified by Experts

Since the tank is open, velocity of efflux can be directly given by Torricelli's law.
`v = sqrt(2 gh)" "...(i)`
Height h corresponds to a gauge pressure 2 `xx 10^(5) N m^(-2)`
`rArr rho gh = 2 xx 10^(5) N m^(-2)`
`rArr gh = (2 xx 10^(5))/(rho)`
`rArr gh = (2 xx 10^(5))/(10^(3))" "[rho = "density of water" = 10^(3) kg m^(-3)]`
Substituting this value of gh in equation (i)
`rArr v = sqrt((2 xx 2 xx 10^(5))/(10^(3)))`
v = 20 m `s^(-1)`
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