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A raindrop of radius 0.2 mm falls throug...

A raindrop of radius 0.2 mm falls through air: If the viscosity of air is 18 `xx 10^(-6)` Pl, find the viscous drag acting on the drop when its speed is 1 m `s^(-1)`.

Text Solution

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Radius of raindrop, a = 0.2 mm
= 0.2 `xx 10^(-3)`m
Air viscosity `eta = 18 xx 10^(-6)` PI
Speed of fall of raindrop, v = 1 m `s^(-1)`
From Stokes' law
Viscous force F = 6 `pi eta a v`
`= 6 pi xx 18 xx 10^(-6) xx 0.2 xx 10^(-3) xx 1`
= 67.8 `xx 10^(-9) N`
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