The surface tension of a soap solution is `30 xx 10^(-3) N m^(-1)`. How much work is done to increase the radius of a soap bubble from 1.5 cm to 3 cm?

Explanation

To solve the problem of calculating the work done to increase the radius of a soap bubble from 1.5 cm to 3 cm, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Surface tension of the soap solution, \( \gamma = 30 \times 10^{-3} \, \text{N/m} \)
- Initial radius of the bubble, \( r_1 = 1.5 \, \text{cm} = 0.015 \, \text{m} \)
- Final radius of the bubble, \( r_2 = 3 \, \text{cm} = 0.03 \, \text{m} \)
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