The work done to get `n` smaller equal size spherical drops from a bigger size spherical drop of wate is proportional to :

Options

A. `(1)/(n^(2//3))-1`
B. `(1)/(n^(1//3))-1`
C. `n^(1//3) -1`
D. `n^(4//3) - 1`

Answer

C