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Obtain the equation of S.H.M. of a parti...

Obtain the equation of S.H.M. of a particle whose amplitude is 0.02,and whose frequency is 25 Hz. The initial phase is `(pi)/(4)`
Hint `: x= A sin ( omegat +phit)`
`omega = 2pi v`

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`x A sin ( omega t + phi)`
`= 0.02 sin ( 2pi xx 25 t + ( pi)/(4))`
`= 0.02 sin ( 50 pi t + ( pi)/(4))`
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