A harmonic osciallation is represented by `x=0.25 cos ( 6000t + 0.85)` ,where x and t are in mm and second respectively . Deduce (i) amplitude , (ii) frequency (iii) angular frequency
Hint `: ` Compare with `x= A cos ( omega t + phi)` a is amplitude frequency , `v = ( omega)/(2pi) , omega = 6000 rad s^(-1)`

Explanation

To solve the problem step by step, we will analyze the given equation of harmonic oscillation and extract the required parameters: amplitude, frequency, and angular frequency.

Given:
\[ x = 0.25 \cos(6000t + 0.85) \]

### Step 1: Identify the Amplitude
The standard form of the equation for harmonic oscillation is:
\[ x = A \cos(\omega t + \phi) \]
...