Plot the corresponding reference circle for given SHM `x = 2 cos ((pi)/(3) -t)` .Indicate the initial `( t- 0)` position of the particle , the radius of the circle and the angular speed of the rotating particle . Consider anticlockwise direction for rotation.
Hint `:` `x = 2 cos ((pi)/(3) -t)=2 cos ( t- (pi)/(3)) ` as ` cos ( - theta) = cos theta` . Compare with `x= A cos ( omegat + phi)`

Explanation

`x=2 cos ((pi)/(3) - t)`
` = 2 cos ( t - ( pi)/(3)) ` as ` cos ( - theta) = cos theta`
Compare with `x= A cos( omegat +phit)`
`A= 2 , omega =1 , phit = - (pi)/( 3)`
The reference circle is as shown in figure