A 10 kg collar is attached to a spring of spring constant `1000 Nm^(-1)` . It slides without friction over a horizontal surface. If is displaced from its equilibrium position by 20 cm and released . Calculate
(a) The period of oscillation (b) The maximum speed
Hint `: T= 2pi sqrt((m)/(k)) , v_(m) = A omega = A sqrt((k)/(m))`

Explanation

`T= 2pi sqrt((m)/(k)) = 2pi sqrt((10)/(1000)) =0.63 s`
The velocity of the collar executing SHM is given by `v(t) = - A omega sin ( omega t + phi)`
The maximum speed is given by ` v_(m)= Aomega`
`=0.2 xx sqrt((1000)/( 10)) = 2ms^(-1)`