A simple pendulum with a metallic bob has a time period T.The bob is now immersed in a non-viscous liquid and oscillated . If the density of the liuid is `(1)/(4)` thatof metal , what will be the time period of the same pendulum?
Hint `:` If the solid bob of the pendulum has relative densty D and has been submerged in in a non-viscous liquid of relative density `rho` then effective acceleration due to gravity `g' = g-(g)/(n) ` where `h = (D)/( rho)`

Explanation

To find the new time period of the pendulum when the bob is submerged in a non-viscous liquid, we can follow these steps:

### Step 1: Understand the given information
- The time period of the simple pendulum in air is \( T \).
- The density of the liquid is \( \frac{1}{4} \) that of the metallic bob.

### Step 2: Define the relative density
Let:
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