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If the inertial mass m(1) of the bob of ...

If the inertial mass `m_(1)` of the bob of a simple pendulum of length 'l' is not equal to the gravitationalmass`m_(g)`, then its period is

A

`T=2pi sqrt((m_(i)l)/(m_(g).g))`

B

`T= 2pi sqrt((m_(g).l)/(m_(i).g))`

C

`T = 2pi sqrt((l)/(g))`

D

`T = 2pi sqrt(((m_(i) + m_(g)))/((m_(i) - m_(g))).(l)/(g))`

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