Home
Class 12
PHYSICS
A mass of 0.5 kg is hung from a spring....

A mass of 0.5 kg is hung from a spring. Agradually increasing 0.5 N force is reuired topull the mass downward a distance of 0.25 m from its equilibrium position,if the mass s then released from this position, find
(a) The total energy of the system .
(b) The frequency of the oscillation
(c ) The speed and acceleration of the mass as it passes the equilibrium position.
(d) The speed and acceleration of the mas when the diplacement from equilibrium is 0.25 m
(e) For the initial condition stated, write down the diplacement equation of motion for this mass.

Text Solution

Verified by Experts

(a) 0.0625J,
(b) `(1)/(pi) Hz`
(c ) 0.5 m//s and 0,
(d) 0 and `1 m//s^(2)
(e ) `0.25 cos ( 2t)`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION-J )|8 Videos
  • OSCILLATIONS

    AAKASH INSTITUTE|Exercise EXAMPLE|21 Videos
  • OSCILLATIONS

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION-H ( MULTIPLE TRUE-FALSE TYPE QUESTIONS) )|3 Videos
  • NUCLEI

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-D)|10 Videos
  • PHYSICAL WORLD

    AAKASH INSTITUTE|Exercise ASSIGNMENT (Section-B)|5 Videos

Similar Questions

Explore conceptually related problems

Find the time period of mass M when displaced from its equilibrium position and then released for the system shown in figure.

A particle is attached to a vertical spring and is pulled down a distance 0.04m below its equilibrium position and is released from rest. The initial upward acceleration of the particle is 0.30 ms^(-2) . The period of the oscillation is

A mass of 1.5 kg is connected to two identical springs each of force constant 300 Nm^(-1) as shown in the figure. If the mass is displaced from its equilibrium position by 10cm, then the period of oscillation is

Given that the equation of motion of a mass is x = 0.20 sin (3,0 t) m . Find the velocity and acceleration of the mass when the object is 5 cm from its equilibrium position. Repeat for x = 0 .

A mass of 1.5 kg is connected to two identical springs each of force constant 300 Nm^(-1) as shown in the figure. If the mass is displaced from its equilibrium position by 10 cm, then maximu speed of the trolley is

A block of mass m length force a verical of spring constant k If the block is polled down by a distance of 2mg//k from its equilibrium position and released for the subsequent in the spring to maximum compressed in it mg//k

A mass of 2kg is attached to the spring of spring constant 50Nm^(-1) . The block is pulled to a distance of 5 cm from its equilibrium position at x=0 on a horizontal frictionless surface from rest at t=0. Write the expression for its displacement at anytime t.

A block whose mass m is 680g is fastened to a spring whose spring constant k is 65N/m. The block is pulled a distance x=11cm from its equilibrium position at x=0 on a frictionless surface and released from rest at t= 0. What is the amplitude of the oscillation?

The acceleration of a simple harmonic oscillator is 1 m//s^(2) when its displacement from mean position is 0.5 m. Then its frequency of oscillation is