Two waves represented by `y=a" "sin(omegat-kx) and y=a" " sin(omega-kx+(2pi)/(3))` are superposed. What will be the amplitude of the resultant wave?

Explanation

To find the amplitude of the resultant wave formed by the superposition of two waves given by the equations \( y_1 = a \sin(\omega t - kx) \) and \( y_2 = a \sin(\omega t - kx + \frac{2\pi}{3}) \), we can follow these steps:

### Step 1: Identify the Phase Difference
The two waves have a phase difference \( \phi \) given by the term \( \frac{2\pi}{3} \) in the second wave.

### Step 2: Use the Formula for Resultant Amplitude
The formula for the amplitude \( A_r \) of the resultant wave when two waves of the same amplitude \( A \) interfere with a phase difference \( \phi \) is given by:
\[
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