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A transverse sinusoidal wave of amplitud...

A transverse sinusoidal wave of amplitude A, wavelength `lamda` and frequency f is travelling along a stretch string. The maximum speed of any point on the string is `(v)/(10)`, where, V is the velocity of wave propagation. If `A=10^(-3)m, and V=10ms^(-1)`, then `lamda` and f are given by

A

`lamda=2pixx10^(-2)m`

B

`lamda=10^(-2)m`

C

`f=(10^(3))/(2pi)Hz`

D

`f=10^(4)Hz`

Text Solution

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The correct Answer is:
A, C
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Knowledge Check

  • A transverse sinusoidal wave of amplitude a, wavelength lambda and frequency f is travelling on a stretched string. The maximum speed of any point in the string is v//10 , where v is the speed of propagation if the wave. If a = 10^(-3)m and v = 10ms^(-1) , then lanbda and f are given by

    A
    (a) `lambda = 2pi xx 10^(-2)m`
    B
    (b) `lambda = 10^(-3)m`
    C
    ( c ) `f = 10^(3) Hz//(2pi)`
    D
    (d) `f = 10^(4)Hz`
  • A transverse wave, whose amplitude is 0.5 m wavelength is 1 m and frequency is 2Hz. is travelling along positive x direction. The equation of this wave will be-

    A
    `y = 0.5 cos (2pix - 4pit)`
    B
    `y = 0.5 cos (2pix - 4pit)`
    C
    `y = 0.5 sin (pix - 2pit)`
    D
    `y = 0.5 cos (2pix - 2pit)`
  • A transverse wave of amplitude 0.50 m, wavelength 1 m and frequency 2 hertz is propagating in a string in the negative x-direction. The expression form of the wave is

    A
    ` y(x,t)=0.5 sin (2pix-4pit)`
    B
    ` y(x,t)=0.5 cos (2pix+4pit)`
    C
    ` y(x,t)=0.5 sin (pix+2pit)`
    D
    ` y(x,t)=0.5 cos (2pix+2pit)`
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