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A carnot engine has efficiency of 60%. I...

A carnot engine has efficiency of 60%. If the source is at `527^(@)C`, then find the temperature of sink.

Text Solution

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Here `T_(1)=527^(@)C=527+273=800K`
`eta=60%=1-(T_(2))/(T_(1))`
`therefore(60)/(100)=1-(T_(2))/(800)`
`therefore(T_(2))/(800)=(40)/(100)`
`thereforeT_(2)=320`K or `47^(@)C`.
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