Home
Class 12
PHYSICS
One mole of an ideal monoatomic gas unde...

One mole of an ideal monoatomic gas undergoes the process `T=T_(0)+4V`, where `T_(0)` is initial temperature. Find
(i) Heat capacity of gas as function of its volume.
(ii) The amount of heat transferred to gas if its volume increases from `V_(0)` to `4V_(0)`.

Text Solution

Verified by Experts

(i) `C=(R)/(4)(10+(T_(0))/(V))`
(ii) `Q=30RV_(0)+RT_(0)ln4`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise Assignment (Section-J) Aakash Challengers Questions|5 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise EXAMPLE|44 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise Assignment (Section-H) Multiple True-False Type Question|2 Videos
  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE|Exercise Assignment (Section-J) Akash Challengers Questions|7 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - D)|15 Videos

Similar Questions

Explore conceptually related problems

One mole of an ideal gas with heat capacity at constant pressure C_p undergoes the process T = T_0 + alpha V , where T_0 and alpha are constants. Find : (a) heat capacity of the gas as a function of its volume , (b) the amount of heat transferred to the gas, if its volume increased from V_1 to V_2 .

One mole an ideal gas whose adiabatic exponent equals gamma undergoes a process p = p_0 + alpha//V , where p_0 and alpha are positive constants. Find : (a) heat capacity of the gas as a function of its volume , (b) the internal energy of heat transferred to the gas, of its volume increased from V_1 to V_2 .

One mole of an ideal gas with adiabatic exponent gamma undergoes the process (a) P=P_0+(alpha)/(V) (b) T=T_0+alphaV Find Molar heat capacity of the gas as a function of its volume.

One mole of a monoatomic ideal gas undergoes a thermodynamic process such that V^3/T^2 = constant. Then,

One mole of an ideal gas with heat capacity at constant pressure C_(P) undergoes the process T=T_(0)+alpha V where T_(0) and a are constants.If its volume increases from V_(1)toV_(2) the amount of heat transferred to the gas is C_(P)RT_(0)ln((V_(2))/(V_(1))) O alpha C_(P)((V_(2)-V_(1)))/(RT_(0))ln((V_(2))/(V_(1))) qquad alpha C_(P)(V_(2)-V_(1))+RT_(0)ln((V_(2))/(V_(1)))

One mole of an ideal gas with heat capacity at constant pressure C_(P) undergoes the process T=T_(0)+alpha V where T_(0) and a are constants.If its volume increases from V_(1)toV_(2) the amount of heat transferred to the gas is C_(P)RT_(0)ln((V_(2))/(V_(1))) alpha C_(P)((V_(2)-V_(1)))/(RT_(0))ln((V_(2))/(V_(1))) alpha C_(P)(V_(2)-V_(1))+RT_(0)ln((V_(2))/(V_(1)))

One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V)/(V_(0)))^(2)) where p_(0) and V_(0) are constants. Find temperature of the gaas when V=V_(0) .

One mole of an ideal gas undergoes a process in which T = T_(0) + aV^(3) , where T_(0) and a are positive constants and V is molar volume. The volume for which pressure with be minimum is

One mole of an ideal gas with heat capacity C_V goes through a process in which its entropy S depends on T as S = alpha//T , where alpha is a constant. The gas temperature varies from T_1 to T_2 Find : (a) the molar heat capacity of the gas as function of its temperature , (b) the amount of heat transferred to the gas , ( c) the work performed by the gas.

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT= K, where K is a constant. In this process the temperataure of the gas is increased by DeltaT . The amount of heat absorbed by gas is (R is gas constant).