Home
Class 12
PHYSICS
A body colls in 7 minutes fro 60^(@)C to...

A body colls in 7 minutes fro `60^(@)C` to `40^(@)C`. What will be its temperature after the next 7 minutes? The temperature of the surroundings is `10^(@)C`.

Text Solution

Verified by Experts

In the first case,
`T_(1)=60^(@),T_(2)=40^(@)C,T_(0)=10^(@)C,t=7` min from `ln((T_(1)-T_(0))/(T_(2)-T_(0)))=Kt`
we get,
`ln((60-10)/(40-10))=7K`
`"ln"(5)/(3)=7K`
In the second case,
If T is the temperature after next 7 min, `T_(1)=40^(@),T_(2)=T,T_(0)=10^(@)C,t=7` min
`"ln"((40-10))/((T-10))=7K`
`"ln"(30)/(T-10)=7K` . . . (ii)
From equation (i) & (ii)
`"ln"(5)/(3)="ln"(30)/(T-10)`
`(5)/(3)=(30)/(T-10)`
`T=28^(@)C`
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE|Exercise Try Youself|16 Videos

  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE|Exercise Assignment (Section-A) Objective Type questions (one option is correct)|50 Videos

  • TEST 9

    AAKASH INSTITUTE|Exercise EXAMPLE|61 Videos

  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION -D) (Assertion - Reason Type Questions)|10 Videos

Similar Questions

Explore conceptually related problems

A body cools in 7 minutes from 60^(@)C to 40^(@)C . What will be its temperature after the next 7 minutes? The temperature of the surrounding is 10^(@)C . Assume that Newton's law of cooling holds good throughout the process.

A body cools in 10 minutes from 60^@C to 40^@C . What will be its temperature after next 10 minutes? The temperature of the surroundings is 10^@C .

A body cools in 7 minute from 60C to 40C .What will be its temperature after the next 7 minute? The temperature of surroundings is 10C

A body cools in 7 min from 60^@C to 40^@C What will be its temperature after the next 7 min? The temperature of surroundings is 10^@C .

A body cools in 10 minutes from 60^(@)C to 40^(@)C . What is the temperature of the body after next 20 minutes? The temperatuer fo surroundings is 10^(@)C

A hot body at 70^@C cools to 25^@ C in 15 min . Find its temperature after the next 10 mins. The temperature of the surroundings is 10^@C .

A body cools from 60°C to 50°C in 9 minutes. What will be the temperature after next 9 minutes? [Temperature of surrounding is 20°C ]

A body cools from 60^(@)C to 52^(@)C in 5 minutes what will be the further fall in its temperature in the next five minutes? If the temperature of the surrounding is 28^(@)C

Hot water cools from 60^(@)C to 50^(@)C in the first 10 minutes and to 45^(@)C in the next 10 minutes. The temperature of the surroundings is: