Home
Class 12
PHYSICS
The magnetic field applied in a cyclotro...

The magnetic field applied in a cyclotron is 3.5 T. What will be the frequency of electric field that must be applied between the does in order to accelerate protons ?

Text Solution

Verified by Experts

`f = (Bq)/(2pi m)`
`= (3.5 xx 1.6 xx 10^(-10))/(2 xx 3.14 xx 1.6 xx 10^(-27))`
`= 5.35 xx 10^(7) Hz`
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE|Exercise Illustration|12 Videos
  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE|Exercise Try Yourself|27 Videos
  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE|Exercise SECTION D|16 Videos
  • NUCLEI

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION-D)|10 Videos

Similar Questions

Explore conceptually related problems

The magnetic flux density applied in a cyclotron is 3*5T . What will be the frequency of electric field that must be applied between the dees in order (a) to accelerate protons (b) alpha -particles? mass of proton 1*67xx10^(-27)kg .

When electric field is applied, the cathode rays bend towards _____

In a Coolidge tube, an electric field is applied

The radius of dees in a cyclotron is 1.9 m and the magnetic field applied on the cyclotron is 0.8 T. Calculate the energy gained by an emergent proton in cyclotron in keV. Mass of proton is 1.67 xx 10^(-27) kg.

In the above question, if an external magnetic field is applied, then the answer is :

A strong magnetic field is applied on a stationary electron, then

Protons are accelerated in a cyclotron using a magnetic field of 1.3 T. Calculate the frequency with which the electric field between the dees should be reversed.