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A current carrying conductor of length l...

A current carrying conductor of length `l` is bent into two loops one by one. First loop has one turn of wire and the second loop has two turns of wire. Compare the magnetic fields at the centre of the loops

Text Solution

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In first case, `l = 2pi r_(1)`, In second case, `l' = 2 xx (2pi r_(2)) rArr r_(2) = r_(1)//2)`
At centre, `B = (mu_(0) i)/(2r_(1)) " " B' = (2 xx mu_(0) i)/(2r_(2))` (`:'` there are 2 turns)
`rArr (B')/(B) = (2r_(1))/(r_(2)) = 4`
`:. B' = 4B`
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