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What is work done on dipole to rotate it...

What is work done on dipole to rotate it form stable equilibrium position `(theta_(1) = 0^(@))` to unstable equilibrium `(theta_(2) = 180^(@))` ?

Text Solution

Verified by Experts

w = MB `(cos theta_(1) - cos theta_(2))`
`= MB [cos 0^(@) - cos 180^(@)]`
=` MB[1-(-1)]`
w = 2 MB
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AAKASH INSTITUTE-MAGNETISM AND MATTER -ASSIGNMENT (SECTION D)
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